79-9z=4(z-3)

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Solution for 79-9z=4(z-3) equation: 



79-9z=4(z-3)

We move all terms to the left:

79-9z-(4(z-3))=0



We calculate terms in parentheses: -(4(z-3)), so:

4(z-3)

We multiply parentheses

4z-12

Back to the equation:

-(4z-12)



We get rid of parentheses

-9z-4z+12+79=0

We add all the numbers together, and all the variables

-13z+91=0

We move all terms containing z to the left, all other terms to the right

-13z=-91

z=-91/-13

z=+7

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