7=((2x)/(0.42-x))

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Solution for 7=((2x)/(0.42-x)) equation: 


D( x )

0.42-x = 0

0.42-x = 0

0.42-x = 0

0.42-x = 0 // - 0.42

-x = -0.42 // * -1

x = 0.42

x in (-oo:0.42) U (0.42:+oo)

7 = (2*x)/(0.42-x) // - (2*x)/(0.42-x)

7-((2*x)/(0.42-x)) = 0

7-2*x*(0.42-x)^-1 = 0

(-2*x)/(0.42-x)+7 = 0

(-2*x)/(0.42-x)+(7*(0.42-x))/(0.42-x) = 0

7*(0.42-x)-2*x = 0

2.94-9*x = 0

(2.94-9*x)/(0.42-x) = 0

(2.94-9*x)/(0.42-x) = 0 // * 0.42-x

2.94-9*x = 0

2.94-9*x = 0 // - 2.94

-9*x = -2.94 // : -9

x = -2.94/(-9)

x = 0.32666667

x = 0.32666667

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