7=(-2)/(3k-12)

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Solution for 7=(-2)/(3k-12) equation: 



7=(-2)/(3k-12)

We move all terms to the left:

7-((-2)/(3k-12))=0



Domain of the equation: (3k-12))!=0

k∈R



We multiply all the terms by the denominator


-((-2)+7*(3k-12))=0



We calculate terms in parentheses: -((-2)+7*(3k-12)), so:

(-2)+7*(3k-12)

determiningTheFunctionDomain
7*(3k-12)+(-2)

We add all the numbers together, and all the variables

7*(3k-12)-2

We multiply parentheses

21k-84-2

We add all the numbers together, and all the variables

21k-86

Back to the equation:

-(21k-86)



We get rid of parentheses

-21k+86=0

We move all terms containing k to the left, all other terms to the right

-21k=-86

k=-86/-21

k=4+2/21

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