7=(-5)(n-4)-3

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Solution for 7=(-5)(n-4)-3 equation: 



7=(-5)(n-4)-3

We move all terms to the left:

7-((-5)(n-4)-3)=0

We multiply parentheses ..

-((-5n+20)-3)+7=0



We calculate terms in parentheses: -((-5n+20)-3), so:

(-5n+20)-3

We get rid of parentheses

-5n+20-3

We add all the numbers together, and all the variables

-5n+17

Back to the equation:

-(-5n+17)



We get rid of parentheses

5n-17+7=0

We add all the numbers together, and all the variables

5n-10=0

We move all terms containing n to the left, all other terms to the right

5n=10

n=10/5

n=2

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