7=(-8/y-3)

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Solution for 7=(-8/y-3) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

7 = -8/y-3 // + -8/y-3

3-(-8/y)+7 = 0

8*y^-1+3+7 = 0

8*y^-1 = -10 // : 8

y^-1 = -5/4

-1 < 0

1/(y^1) = -5/4 // * y^1

1 = -5/4*y^1 // : -5/4

-4/5 = y^1

y = -4/5

y = -4/5

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