7=(2a+3)-(4a-8)

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Solution for 7=(2a+3)-(4a-8) equation: 



7=(2a+3)-(4a-8)

We move all terms to the left:

7-((2a+3)-(4a-8))=0



We calculate terms in parentheses: -((2a+3)-(4a-8)), so:

(2a+3)-(4a-8)

We get rid of parentheses

2a-4a+3+8

We add all the numbers together, and all the variables

-2a+11

Back to the equation:

-(-2a+11)



We get rid of parentheses

2a-11+7=0

We add all the numbers together, and all the variables

2a-4=0

We move all terms containing a to the left, all other terms to the right

2a=4

a=4/2

a=2

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