7=(36+45y/3)-2y

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Solution for 7=(36+45y/3)-2y equation: 



7=(36+45y/3)-2y

We move all terms to the left:

7-((36+45y/3)-2y)=0



Domain of the equation: 3)-2y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

-((45y/3+36)-2y)+7=0

We multiply all the terms by the denominator


-((45y+7*3+36)-2y)=0



We calculate terms in parentheses: -((45y+7*3+36)-2y), so:

(45y+7*3+36)-2y

We add all the numbers together, and all the variables

(45y+57)-2y

We add all the numbers together, and all the variables

-2y+(45y+57)

We get rid of parentheses

-2y+45y+57

We add all the numbers together, and all the variables

43y+57

Back to the equation:

-(43y+57)



We get rid of parentheses

-43y-57=0

We move all terms containing y to the left, all other terms to the right

-43y=57

y=57/-43

y=-1+14/43

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