7=(3c-11)+-6c

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Solution for 7=(3c-11)+-6c equation: 



7=(3c-11)+-6c

We move all terms to the left:

7-((3c-11)+-6c)=0

We use the square of the difference formula

-((3c-11)-6c)+7=0



We calculate terms in parentheses: -((3c-11)-6c), so:

(3c-11)-6c

We add all the numbers together, and all the variables

-6c+(3c-11)

We get rid of parentheses

-6c+3c-11

We add all the numbers together, and all the variables

-3c-11

Back to the equation:

-(-3c-11)



We get rid of parentheses

3c+11+7=0

We add all the numbers together, and all the variables

3c+18=0

We move all terms containing c to the left, all other terms to the right

3c=-18

c=-18/3

c=-6

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