7=(4/3)(x+6)

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Solution for 7=(4/3)(x+6) equation: 



7=(4/3)(x+6)

We move all terms to the left:

7-((4/3)(x+6))=0



Domain of the equation: 3)(x+6))!=0

x∈R



We add all the numbers together, and all the variables

-((+4/3)(x+6))+7=0

We multiply parentheses ..

-((+4x^2+4/3*6))+7=0

We multiply all the terms by the denominator


-((+4x^2+4+7*3*6))=0



We calculate terms in parentheses: -((+4x^2+4+7*3*6)), so:

(+4x^2+4+7*3*6)

We get rid of parentheses

4x^2+4+7*3*6

We add all the numbers together, and all the variables

4x^2+130

Back to the equation:

-(4x^2+130)



We get rid of parentheses

-4x^2-130=0

a = -4; b = 0; c = -130;
Δ = b2-4ac
Δ = 02-4·(-4)·(-130)
Δ = -2080
Delta is less than zero, so there is no solution for the equation

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