7=(5/2)+x

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Solution for 7=(5/2)+x equation: 



7=(5/2)+x

We move all terms to the left:

7-((5/2)+x)=0



Domain of the equation: 2)+x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+5/2)+x)+7=0

We multiply all the terms by the denominator


-((+5+7*2)+x)=0



We calculate terms in parentheses: -((+5+7*2)+x), so:

(+5+7*2)+x

determiningTheFunctionDomain
x+(+5+7*2)

We add all the numbers together, and all the variables

x+19

Back to the equation:

-(x+19)



We get rid of parentheses

-x-19=0

We add all the numbers together, and all the variables

-1x-19=0

We move all terms containing x to the left, all other terms to the right

-x=19

x=19/-1

x=-19

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