7=(70-42x)/9

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Solution for 7=(70-42x)/9 equation:



7=(70-42x)/9
We move all terms to the left:
7-((70-42x)/9)=0
We add all the numbers together, and all the variables
-((-42x+70)/9)+7=0
We multiply all the terms by the denominator
-((-42x+70)+7*9)=0
We calculate terms in parentheses: -((-42x+70)+7*9), so:
(-42x+70)+7*9
We add all the numbers together, and all the variables
(-42x+70)+63
We get rid of parentheses
-42x+70+63
We add all the numbers together, and all the variables
-42x+133
Back to the equation:
-(-42x+133)
We get rid of parentheses
42x-133=0
We move all terms containing x to the left, all other terms to the right
42x=133
x=133/42
x=3+1/6

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