7=(k+4)/3

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Solution for 7=(k+4)/3 equation: 



7=(k+4)/3

We move all terms to the left:

7-((k+4)/3)=0

We multiply all the terms by the denominator


-((k+4)+7*3)=0



We calculate terms in parentheses: -((k+4)+7*3), so:

(k+4)+7*3

We add all the numbers together, and all the variables

(k+4)+21

We get rid of parentheses

k+4+21

We add all the numbers together, and all the variables

k+25

Back to the equation:

-(k+25)



We get rid of parentheses

-k-25=0

We add all the numbers together, and all the variables

-1k-25=0

We move all terms containing k to the left, all other terms to the right

-k=25

k=25/-1

k=-25

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