7=+12/6-(2x-4)

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Solution for 7=+12/6-(2x-4) equation: 



7=+12/6-(2x-4)

We move all terms to the left:

7-(+12/6-(2x-4))=0



Domain of the equation: 6-(2x-4))!=0

We move all terms containing x to the left, all other terms to the right

-(2x-4))!=-6

x∈R



We multiply all the terms by the denominator


-(+12+7*6-(2x-4))=0



We calculate terms in parentheses: -(+12+7*6-(2x-4)), so:

+12+7*6-(2x-4)

determiningTheFunctionDomain
-(2x-4)+12+7*6

We add all the numbers together, and all the variables

-(2x-4)+54

We get rid of parentheses

-2x+4+54

We add all the numbers together, and all the variables

-2x+58

Back to the equation:

-(-2x+58)



We get rid of parentheses

2x-58=0

We move all terms containing x to the left, all other terms to the right

2x=58

x=58/2

x=29

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