7=-11+3(b+5)=

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Solution for 7=-11+3(b+5)= equation: 



7=-11+3(b+5)=

We move all terms to the left:

7-(-11+3(b+5))=0



We calculate terms in parentheses: -(-11+3(b+5)), so:

-11+3(b+5)

determiningTheFunctionDomain
3(b+5)-11

We multiply parentheses

3b+15-11

We add all the numbers together, and all the variables

3b+4

Back to the equation:

-(3b+4)



We get rid of parentheses

-3b-4+7=0

We add all the numbers together, and all the variables

-3b+3=0

We move all terms containing b to the left, all other terms to the right

-3b=-3

b=-3/-3

b=1

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