7=-25+3(b+5)

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Solution for 7=-25+3(b+5) equation: 



7=-25+3(b+5)

We move all terms to the left:

7-(-25+3(b+5))=0



We calculate terms in parentheses: -(-25+3(b+5)), so:

-25+3(b+5)

determiningTheFunctionDomain
3(b+5)-25

We multiply parentheses

3b+15-25

We add all the numbers together, and all the variables

3b-10

Back to the equation:

-(3b-10)



We get rid of parentheses

-3b+10+7=0

We add all the numbers together, and all the variables

-3b+17=0

We move all terms containing b to the left, all other terms to the right

-3b=-17

b=-17/-3

b=5+2/3

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