7=1+(2/3)x

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Solution for 7=1+(2/3)x equation: 



7=1+(2/3)x

We move all terms to the left:

7-(1+(2/3)x)=0



Domain of the equation: 3)x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-(1+(+2/3)x)+7=0

We multiply all the terms by the denominator


-(1+(+2+7*3)x)=0



We calculate terms in parentheses: -(1+(+2+7*3)x), so:

1+(+2+7*3)x

determiningTheFunctionDomain
(+2+7*3)x+1

We add all the numbers together, and all the variables

23x+1

Back to the equation:

-(23x+1)



We get rid of parentheses

-23x-1=0

We move all terms containing x to the left, all other terms to the right

-23x=1

x=1/-23

x=-1/23

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