7=1/3(c-1)

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Solution for 7=1/3(c-1) equation: 



7=1/3(c-1)

We move all terms to the left:

7-(1/3(c-1))=0



Domain of the equation: 3(c-1))!=0

c∈R



We multiply all the terms by the denominator


-(1+7*3(c-1))=0



We calculate terms in parentheses: -(1+7*3(c-1)), so:

1+7*3(c-1)

determiningTheFunctionDomain
7*3(c-1)+1

Wy multiply elements

21c(c+1

Back to the equation:

-(21c(c+1)





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21c(c+1





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21c(c+1





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