7=1/5(p-15)

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Solution for 7=1/5(p-15) equation: 



7=1/5(p-15)

We move all terms to the left:

7-(1/5(p-15))=0



Domain of the equation: 5(p-15))!=0

p∈R



We multiply all the terms by the denominator


-(1+7*5(p-15))=0



We calculate terms in parentheses: -(1+7*5(p-15)), so:

1+7*5(p-15)

determiningTheFunctionDomain
7*5(p-15)+1

Wy multiply elements

35p(p+1

Back to the equation:

-(35p(p+1)





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1





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35p(p+1

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