7=11+3(b+4)

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Solution for 7=11+3(b+4) equation: 



7=11+3(b+4)

We move all terms to the left:

7-(11+3(b+4))=0



We calculate terms in parentheses: -(11+3(b+4)), so:

11+3(b+4)

determiningTheFunctionDomain
3(b+4)+11

We multiply parentheses

3b+12+11

We add all the numbers together, and all the variables

3b+23

Back to the equation:

-(3b+23)



We get rid of parentheses

-3b-23+7=0

We add all the numbers together, and all the variables

-3b-16=0

We move all terms containing b to the left, all other terms to the right

-3b=16

b=16/-3

b=-5+1/3

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