7=12-5(2y+1)-6y

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Solution for 7=12-5(2y+1)-6y equation: 



7=12-5(2y+1)-6y

We move all terms to the left:

7-(12-5(2y+1)-6y)=0



We calculate terms in parentheses: -(12-5(2y+1)-6y), so:

12-5(2y+1)-6y

determiningTheFunctionDomain
-5(2y+1)-6y+12

We add all the numbers together, and all the variables

-6y-5(2y+1)+12

We multiply parentheses

-6y-10y-5+12

We add all the numbers together, and all the variables

-16y+7

Back to the equation:

-(-16y+7)



We get rid of parentheses

16y-7+7=0

We add all the numbers together, and all the variables

16y=0

y=0/16

y=0

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