7=2(1/3y+3)-9

Solution for 7=2(1/3y+3)-9 equation:

7=2(1/3y+3)-9

We move all terms to the left:

7-(2(1/3y+3)-9)=0


Domain of the equation: 3y+3)-9)!=0

y∈R


We multiply all the terms by the denominator


-(2(1+7*3y+3)-9)=0


We calculate terms in parentheses: -(2(1+7*3y+3)-9), so:

2(1+7*3y+3)-9

We add all the numbers together, and all the variables

2(7*3y+4)-9

We multiply parentheses

42y+8-9

We add all the numbers together, and all the variables

42y-1

Back to the equation:

-(42y-1)


We get rid of parentheses

-42y+1=0

We move all terms containing y to the left, all other terms to the right

-42y=-1

y=-1/-42

y=1/42