7=2(h+3)-7

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Solution for 7=2(h+3)-7 equation: 



7=2(h+3)-7

We move all terms to the left:

7-(2(h+3)-7)=0



We calculate terms in parentheses: -(2(h+3)-7), so:

2(h+3)-7

We multiply parentheses

2h+6-7

We add all the numbers together, and all the variables

2h-1

Back to the equation:

-(2h-1)



We get rid of parentheses

-2h+1+7=0

We add all the numbers together, and all the variables

-2h+8=0

We move all terms containing h to the left, all other terms to the right

-2h=-8

h=-8/-2

h=+4

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