7=2(y-4)-5y

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Solution for 7=2(y-4)-5y equation:



7=2(y-4)-5y
We move all terms to the left:
7-(2(y-4)-5y)=0
We calculate terms in parentheses: -(2(y-4)-5y), so:
2(y-4)-5y
We add all the numbers together, and all the variables
-5y+2(y-4)
We multiply parentheses
-5y+2y-8
We add all the numbers together, and all the variables
-3y-8
Back to the equation:
-(-3y-8)
We get rid of parentheses
3y+8+7=0
We add all the numbers together, and all the variables
3y+15=0
We move all terms containing y to the left, all other terms to the right
3y=-15
y=-15/3
y=-5

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