7=2(y-4)-5y

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Solution for 7=2(y-4)-5y equation: 



7=2(y-4)-5y

We move all terms to the left:

7-(2(y-4)-5y)=0



We calculate terms in parentheses: -(2(y-4)-5y), so:

2(y-4)-5y

We add all the numbers together, and all the variables

-5y+2(y-4)

We multiply parentheses

-5y+2y-8

We add all the numbers together, and all the variables

-3y-8

Back to the equation:

-(-3y-8)



We get rid of parentheses

3y+8+7=0

We add all the numbers together, and all the variables

3y+15=0

We move all terms containing y to the left, all other terms to the right

3y=-15

y=-15/3

y=-5

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