7=2+5(z+-2)

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Solution for 7=2+5(z+-2) equation: 



7=2+5(z+-2)

We move all terms to the left:

7-(2+5(z+-2))=0

We add all the numbers together, and all the variables

-(2+5(z-2))+7=0



We calculate terms in parentheses: -(2+5(z-2)), so:

2+5(z-2)

determiningTheFunctionDomain
5(z-2)+2

We multiply parentheses

5z-10+2

We add all the numbers together, and all the variables

5z-8

Back to the equation:

-(5z-8)



We get rid of parentheses

-5z+8+7=0

We add all the numbers together, and all the variables

-5z+15=0

We move all terms containing z to the left, all other terms to the right

-5z=-15

z=-15/-5

z=+3

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