7=2/5y=3/5y-4

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Solution for 7=2/5y=3/5y-4 equation: 



7=2/5y=3/5y-4

We move all terms to the left:

7-(2/5y)=0



Domain of the equation: 5y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

-(+2/5y)+7=0

We get rid of parentheses

-2/5y+7=0

We multiply all the terms by the denominator


7*5y-2=0

Wy multiply elements

35y-2=0

We move all terms containing y to the left, all other terms to the right

35y=2

y=2/35

y=2/35

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