7=3(1+6x)+4(1+3x)

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Solution for 7=3(1+6x)+4(1+3x) equation: 



7=3(1+6x)+4(1+3x)

We move all terms to the left:

7-(3(1+6x)+4(1+3x))=0

We add all the numbers together, and all the variables

-(3(6x+1)+4(3x+1))+7=0



We calculate terms in parentheses: -(3(6x+1)+4(3x+1)), so:

3(6x+1)+4(3x+1)

We multiply parentheses

18x+12x+3+4

We add all the numbers together, and all the variables

30x+7

Back to the equation:

-(30x+7)



We get rid of parentheses

-30x-7+7=0

We add all the numbers together, and all the variables

-30x=0

x=0/-30

x=0

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