7=3(c+1)+1

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Solution for 7=3(c+1)+1 equation: 



7=3(c+1)+1

We move all terms to the left:

7-(3(c+1)+1)=0



We calculate terms in parentheses: -(3(c+1)+1), so:

3(c+1)+1

We multiply parentheses

3c+3+1

We add all the numbers together, and all the variables

3c+4

Back to the equation:

-(3c+4)



We get rid of parentheses

-3c-4+7=0

We add all the numbers together, and all the variables

-3c+3=0

We move all terms containing c to the left, all other terms to the right

-3c=-3

c=-3/-3

c=1

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