7=3(n-2)+3n

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Solution for 7=3(n-2)+3n equation: 



7=3(n-2)+3n

We move all terms to the left:

7-(3(n-2)+3n)=0



We calculate terms in parentheses: -(3(n-2)+3n), so:

3(n-2)+3n

We add all the numbers together, and all the variables

3n+3(n-2)

We multiply parentheses

3n+3n-6

We add all the numbers together, and all the variables

6n-6

Back to the equation:

-(6n-6)



We get rid of parentheses

-6n+6+7=0

We add all the numbers together, and all the variables

-6n+13=0

We move all terms containing n to the left, all other terms to the right

-6n=-13

n=-13/-6

n=2+1/6

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