7=3(n-5)-2

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Solution for 7=3(n-5)-2 equation: 



7=3(n-5)-2

We move all terms to the left:

7-(3(n-5)-2)=0



We calculate terms in parentheses: -(3(n-5)-2), so:

3(n-5)-2

We multiply parentheses

3n-15-2

We add all the numbers together, and all the variables

3n-17

Back to the equation:

-(3n-17)



We get rid of parentheses

-3n+17+7=0

We add all the numbers together, and all the variables

-3n+24=0

We move all terms containing n to the left, all other terms to the right

-3n=-24

n=-24/-3

n=+8

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