7=3(x+1)+4(x+1)

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Solution for 7=3(x+1)+4(x+1) equation: 



7=3(x+1)+4(x+1)

We move all terms to the left:

7-(3(x+1)+4(x+1))=0



We calculate terms in parentheses: -(3(x+1)+4(x+1)), so:

3(x+1)+4(x+1)

We multiply parentheses

3x+4x+3+4

We add all the numbers together, and all the variables

7x+7

Back to the equation:

-(7x+7)



We get rid of parentheses

-7x-7+7=0

We add all the numbers together, and all the variables

-7x=0

x=0/-7

x=0

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