7=3(y-3)+y

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Solution for 7=3(y-3)+y equation: 



7=3(y-3)+y

We move all terms to the left:

7-(3(y-3)+y)=0



We calculate terms in parentheses: -(3(y-3)+y), so:

3(y-3)+y

We add all the numbers together, and all the variables

y+3(y-3)

We multiply parentheses

y+3y-9

We add all the numbers together, and all the variables

4y-9

Back to the equation:

-(4y-9)



We get rid of parentheses

-4y+9+7=0

We add all the numbers together, and all the variables

-4y+16=0

We move all terms containing y to the left, all other terms to the right

-4y=-16

y=-16/-4

y=+4

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