7=3(z+1)-5

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Solution for 7=3(z+1)-5 equation: 



7=3(z+1)-5

We move all terms to the left:

7-(3(z+1)-5)=0



We calculate terms in parentheses: -(3(z+1)-5), so:

3(z+1)-5

We multiply parentheses

3z+3-5

We add all the numbers together, and all the variables

3z-2

Back to the equation:

-(3z-2)



We get rid of parentheses

-3z+2+7=0

We add all the numbers together, and all the variables

-3z+9=0

We move all terms containing z to the left, all other terms to the right

-3z=-9

z=-9/-3

z=+3

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