7=4(5y+8)=2(2y+1)+5

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Solution for 7=4(5y+8)=2(2y+1)+5 equation: 



7=4(5y+8)=2(2y+1)+5

We move all terms to the left:

7-(4(5y+8))=0



We calculate terms in parentheses: -(4(5y+8)), so:

4(5y+8)

We multiply parentheses

20y+32

Back to the equation:

-(20y+32)



We get rid of parentheses

-20y-32+7=0

We add all the numbers together, and all the variables

-20y-25=0

We move all terms containing y to the left, all other terms to the right

-20y=25

y=25/-20

y=-1+1/4

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