7=4(7j-6)+3

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Solution for 7=4(7j-6)+3 equation: 



7=4(7j-6)+3

We move all terms to the left:

7-(4(7j-6)+3)=0



We calculate terms in parentheses: -(4(7j-6)+3), so:

4(7j-6)+3

We multiply parentheses

28j-24+3

We add all the numbers together, and all the variables

28j-21

Back to the equation:

-(28j-21)



We get rid of parentheses

-28j+21+7=0

We add all the numbers together, and all the variables

-28j+28=0

We move all terms containing j to the left, all other terms to the right

-28j=-28

j=-28/-28

j=1

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