7=4-3(2n+5)+6

Solution for 7=4-3(2n+5)+6 equation:

7=4-3(2n+5)+6

We move all terms to the left:

7-(4-3(2n+5)+6)=0


We calculate terms in parentheses: -(4-3(2n+5)+6), so:

4-3(2n+5)+6

determiningTheFunctionDomain
-3(2n+5)+4+6

We add all the numbers together, and all the variables

-3(2n+5)+10

We multiply parentheses

-6n-15+10

We add all the numbers together, and all the variables

-6n-5

Back to the equation:

-(-6n-5)


We get rid of parentheses

6n+5+7=0

We add all the numbers together, and all the variables

6n+12=0

We move all terms containing n to the left, all other terms to the right

6n=-12

n=-12/6

n=-2