7=5(n-4)-3

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Solution for 7=5(n-4)-3 equation: 



7=5(n-4)-3

We move all terms to the left:

7-(5(n-4)-3)=0



We calculate terms in parentheses: -(5(n-4)-3), so:

5(n-4)-3

We multiply parentheses

5n-20-3

We add all the numbers together, and all the variables

5n-23

Back to the equation:

-(5n-23)



We get rid of parentheses

-5n+23+7=0

We add all the numbers together, and all the variables

-5n+30=0

We move all terms containing n to the left, all other terms to the right

-5n=-30

n=-30/-5

n=+6

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