7=5(r+3)=6+3(r-2)

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Solution for 7=5(r+3)=6+3(r-2) equation: 



7=5(r+3)=6+3(r-2)

We move all terms to the left:

7-(5(r+3))=0



We calculate terms in parentheses: -(5(r+3)), so:

5(r+3)

We multiply parentheses

5r+15

Back to the equation:

-(5r+15)



We get rid of parentheses

-5r-15+7=0

We add all the numbers together, and all the variables

-5r-8=0

We move all terms containing r to the left, all other terms to the right

-5r=8

r=8/-5

r=-1+3/5

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