7=6(c+4)-5

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Solution for 7=6(c+4)-5 equation: 



7=6(c+4)-5

We move all terms to the left:

7-(6(c+4)-5)=0



We calculate terms in parentheses: -(6(c+4)-5), so:

6(c+4)-5

We multiply parentheses

6c+24-5

We add all the numbers together, and all the variables

6c+19

Back to the equation:

-(6c+19)



We get rid of parentheses

-6c-19+7=0

We add all the numbers together, and all the variables

-6c-12=0

We move all terms containing c to the left, all other terms to the right

-6c=12

c=12/-6

c=-2

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