7=6(z+3)-5

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Solution for 7=6(z+3)-5 equation: 



7=6(z+3)-5

We move all terms to the left:

7-(6(z+3)-5)=0



We calculate terms in parentheses: -(6(z+3)-5), so:

6(z+3)-5

We multiply parentheses

6z+18-5

We add all the numbers together, and all the variables

6z+13

Back to the equation:

-(6z+13)



We get rid of parentheses

-6z-13+7=0

We add all the numbers together, and all the variables

-6z-6=0

We move all terms containing z to the left, all other terms to the right

-6z=6

z=6/-6

z=-1

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