7=7(r-5)/3

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Solution for 7=7(r-5)/3 equation:



7=7(r-5)/3
We move all terms to the left:
7-(7(r-5)/3)=0
We multiply all the terms by the denominator
-(7(r-5)+7*3)=0
We calculate terms in parentheses: -(7(r-5)+7*3), so:
7(r-5)+7*3
We add all the numbers together, and all the variables
7(r-5)+21
We multiply parentheses
7r-35+21
We add all the numbers together, and all the variables
7r-14
Back to the equation:
-(7r-14)
We get rid of parentheses
-7r+14=0
We move all terms containing r to the left, all other terms to the right
-7r=-14
r=-14/-7
r=+2

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