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7=8y^2+7y
We move all terms to the left:
7-(8y^2+7y)=0
We get rid of parentheses
-8y^2-7y+7=0
a = -8; b = -7; c = +7;
Δ = b2-4ac
Δ = -72-4·(-8)·7
Δ = 273
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{273}}{2*-8}=\frac{7-\sqrt{273}}{-16} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{273}}{2*-8}=\frac{7+\sqrt{273}}{-16} $
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