7=9(8c+2)+3

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Solution for 7=9(8c+2)+3 equation: 



7=9(8c+2)+3

We move all terms to the left:

7-(9(8c+2)+3)=0



We calculate terms in parentheses: -(9(8c+2)+3), so:

9(8c+2)+3

We multiply parentheses

72c+18+3

We add all the numbers together, and all the variables

72c+21

Back to the equation:

-(72c+21)



We get rid of parentheses

-72c-21+7=0

We add all the numbers together, and all the variables

-72c-14=0

We move all terms containing c to the left, all other terms to the right

-72c=14

c=14/-72

c=-7/36

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