7=b/3-5b+2

Solution for 7=b/3-5b+2 equation:

7=b/3-5b+2

We move all terms to the left:

7-(b/3-5b+2)=0


Domain of the equation: 3-5b+2)!=0

We move all terms containing b to the left, all other terms to the right

-5b+2)!=-3

b∈R


We add all the numbers together, and all the variables

-(-5b+b/3+2)+7=0

We get rid of parentheses

5b-b/3-2+7=0

We multiply all the terms by the denominator


5b*3-b-2*3+7*3=0

We add all the numbers together, and all the variables

-1b+5b*3+15=0

Wy multiply elements

-1b+15b+15=0

We add all the numbers together, and all the variables

14b+15=0

We move all terms containing b to the left, all other terms to the right

14b=-15

b=-15/14

b=-1+1/14