7=ln(2.5/x)

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Solution for 7=ln(2.5/x) equation:


D( x )

x = 0

2.5/x <= 0

x = 0

x = 0

2.5/x <= 0

2.5/x <= 0

2.5*x^-1 <= 0

2.5*x^-1 <= 0 // : 2.5

x^-1 <= 0/2.5

x^-1 <= 0

1/(x^1) <= 0

x <> 0

1/(x^1) <= 0 // * x^2

(x^2)/(x^1) <= 0

x^1 <= 0

x <= 0

x in (-oo:0)

x in (0:+oo)

7 = ln(2.5/x) // - ln(2.5/x)

7-ln(2.5/x) = 0

7-ln(2.5/x) = 0 // - 7

-ln(2.5/x) = -7

-ln(2.5/x) = -7 // * -1

ln(2.5/x) = ln(e^7)

2.5/x = e^7

2.5/x-e^7 = 0

2.5*x^-1 = e^7 // : 2.5

x^-1 = 0.4*e^7

-1 < 0

1/(x^1) = 0.4*e^7 // * x^1

1 = 0.4*e^7*x^1 // : 0.4*e^7

2.5*e^-7 = x^1

x = 2.5*e^-7

x = 2.5*e^-7

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