7=t*2t/2t+t

Solution for 7=t*2t/2t+t equation:

7=t*2t/2t+t

We move all terms to the left:

7-(t*2t/2t+t)=0


Domain of the equation: 2t+t)!=0

t∈R


We add all the numbers together, and all the variables

-(+t+t*2t/2t)+7=0

We get rid of parentheses

-t-t*2t/2t+7=0

We multiply all the terms by the denominator


-t*2t-t*2t+7*2t=0

Wy multiply elements

-2t^2-2t^2+14t=0

We add all the numbers together, and all the variables

-4t^2+14t=0

a = -4; b = 14; c = 0;
Δ = b2-4ac
Δ = 142-4·(-4)·0
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-14}{2*-4}=\frac{-28}{-8}
=3+1/2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+14}{2*-4}=\frac{0}{-8}
=0
$