7=y+3(y-2)

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Solution for 7=y+3(y-2) equation:



7=y+3(y-2)
We move all terms to the left:
7-(y+3(y-2))=0
We calculate terms in parentheses: -(y+3(y-2)), so:
y+3(y-2)
We multiply parentheses
y+3y-6
We add all the numbers together, and all the variables
4y-6
Back to the equation:
-(4y-6)
We get rid of parentheses
-4y+6+7=0
We add all the numbers together, and all the variables
-4y+13=0
We move all terms containing y to the left, all other terms to the right
-4y=-13
y=-13/-4
y=3+1/4

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