7=y+3(y-2)

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Solution for 7=y+3(y-2) equation: 



7=y+3(y-2)

We move all terms to the left:

7-(y+3(y-2))=0



We calculate terms in parentheses: -(y+3(y-2)), so:

y+3(y-2)

We multiply parentheses

y+3y-6

We add all the numbers together, and all the variables

4y-6

Back to the equation:

-(4y-6)



We get rid of parentheses

-4y+6+7=0

We add all the numbers together, and all the variables

-4y+13=0

We move all terms containing y to the left, all other terms to the right

-4y=-13

y=-13/-4

y=3+1/4

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