7I2-(3+4x)4-2x=-9+2(1-15x)

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Solution for 7I2-(3+4x)4-2x=-9+2(1-15x) equation: 



72-(3+4I)4-2I=-9+2(1-15I)

We move all terms to the left:

72-(3+4I)4-2I-(-9+2(1-15I))=0

We add all the numbers together, and all the variables

-(4I+3)4-2I-(-9+2(-15I+1))+72=0

We add all the numbers together, and all the variables

-2I-(4I+3)4-(-9+2(-15I+1))+72=0

We multiply parentheses

-2I-16I-(-9+2(-15I+1))-12+72=0



We calculate terms in parentheses: -(-9+2(-15I+1)), so:

-9+2(-15I+1)

determiningTheFunctionDomain
2(-15I+1)-9

We multiply parentheses

-30I+2-9

We add all the numbers together, and all the variables

-30I-7

Back to the equation:

-(-30I-7)



We add all the numbers together, and all the variables

-18I-(-30I-7)+60=0

We get rid of parentheses

-18I+30I+7+60=0

We add all the numbers together, and all the variables

12I+67=0

We move all terms containing I to the left, all other terms to the right

12I=-67

I=-67/12

I=-5+7/12

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