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7X(4+2X)-4=16+7X
We move all terms to the left:
7X(4+2X)-4-(16+7X)=0
We add all the numbers together, and all the variables
7X(2X+4)-(7X+16)-4=0
We multiply parentheses
14X^2+28X-(7X+16)-4=0
We get rid of parentheses
14X^2+28X-7X-16-4=0
We add all the numbers together, and all the variables
14X^2+21X-20=0
a = 14; b = 21; c = -20;
Δ = b2-4ac
Δ = 212-4·14·(-20)
Δ = 1561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{1561}}{2*14}=\frac{-21-\sqrt{1561}}{28} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{1561}}{2*14}=\frac{-21+\sqrt{1561}}{28} $
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