7a+10=a2

Solution for 7a+10=a2 equation:

7a+10=a2

We move all terms to the left:

7a+10-(a2)=0

We add all the numbers together, and all the variables

-1a^2+7a+10=0

a = -1; b = 7; c = +10;
Δ = b2-4ac
Δ = 72-4·(-1)·10
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{89}}{2*-1}=\frac{-7-\sqrt{89}}{-2}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{89}}{2*-1}=\frac{-7+\sqrt{89}}{-2}
$