7a+3-4a=3-3(a+4)

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Solution for 7a+3-4a=3-3(a+4) equation: 



7a+3-4a=3-3(a+4)

We move all terms to the left:

7a+3-4a-(3-3(a+4))=0

We add all the numbers together, and all the variables

3a-(3-3(a+4))+3=0



We calculate terms in parentheses: -(3-3(a+4)), so:

3-3(a+4)

determiningTheFunctionDomain
-3(a+4)+3

We multiply parentheses

-3a-12+3

We add all the numbers together, and all the variables

-3a-9

Back to the equation:

-(-3a-9)



We get rid of parentheses

3a+3a+9+3=0

We add all the numbers together, and all the variables

6a+12=0

We move all terms containing a to the left, all other terms to the right

6a=-12

a=-12/6

a=-2

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